Mathematics, applications of mathematics to life in general, and my life as a mathematician.
Here is a problem from the 1978 Kyiv Olympiad for 7 graders.
Is it possible to place seven points on a plane so that among any three of them, two will be at distance 1 from each other?
Let ABCD be a parallelogram with AB=BC=CD=DA=BD=1 And let AEFG be another parallelogram with AE=EF=FG=GA=EG=1 Now position both parallelograms in such a way that CF=1 and you are done.
Name (required)
E-Mail (will not be published) (required)
Website
Δ
You can support my website by a donation through PayPal or by shopping at Amazon through this link.
Zarunias:
Let ABCD be a parallelogram with AB=BC=CD=DA=BD=1
12 March 2022, 12:52 pmAnd let AEFG be another parallelogram with AE=EF=FG=GA=EG=1
Now position both parallelograms in such a way that CF=1 and you are done.