Comments on: Meta Solving a Probability Puzzle
https://blog.tanyakhovanova.com/2022/02/meta-solving-a-probability-puzzle/
Mathematics, applications of mathematics to life in general, and my life as a mathematician.Tue, 21 Feb 2023 20:49:06 +0000
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By: 17 Best Mathematics Blogs in 2023 - Mass Blog
https://blog.tanyakhovanova.com/2022/02/meta-solving-a-probability-puzzle/#comment-13674
Tue, 21 Feb 2023 20:49:06 +0000https://blog.tanyakhovanova.com/?p=1583#comment-13674[…] Brimming with uncommon Math information, Dr. Tanya Khovanova manages this exceptional blog. She is a freelance mathematician, a Mathletics coach at the Advanced Math and Sciences Academy in Massachusetts, and a math research coordinator at MIT. Although the website seems outdated, it is still highly active. From algorithms, sequences, statistics, and even math humor, there are plenty of categories to choose from. For starters, take a look at this blog post on how to solve a probability puzzle. […]
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By: 17 Best Mathematics Blogs in 2022 – Mass Blog
https://blog.tanyakhovanova.com/2022/02/meta-solving-a-probability-puzzle/#comment-13399
Sun, 27 Mar 2022 14:49:21 +0000https://blog.tanyakhovanova.com/?p=1583#comment-13399[…] Brimming with uncommon Math information, Dr. Tanya Khovanova manages this exceptional blog. She is a freelance mathematician, a Mathletics coach at the Advanced Math and Sciences Academy in Massachusetts, and a math research coordinator at MIT. Although the website seems outdated, it is still highly active. From algorithms, sequences, statistics, and even math humor, there are plenty of categories to choose from. For starters, take a look at this blog post on how to solve a probability puzzle. […]
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By: Yuzhou Gu
https://blog.tanyakhovanova.com/2022/02/meta-solving-a-probability-puzzle/#comment-13383
Thu, 10 Feb 2022 02:08:32 +0000https://blog.tanyakhovanova.com/?p=1583#comment-13383I am wondering the following: Suppose Alice goes broke with a particular sequence a. If there are k heads, then there are k+100 tails. In the switched sequence b, there are k+100 heads and k tails. So sequence b has 100 (rather than 200) more heads than sequence a, and the ratio between probabilities should be (49/51)^100.
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