Its becomes a paradox only if you think the answer that you are supposed to give is listed in the options.

Before proceeding into answer, lets understand the question. The idea behind the question is to find the probability of getting a correct answer , with one option listed twice.

So, now change the options with below identical ones.

a) RED

b)BLUE

c:) GREEN

d.)RED.

Now , we don’t know whether RED or BLUE or GREEN is correct. Hence, the chance of correct answer becomes 2/4 = 1/2.

It only leads to misconception only if you mess up with options listed in the question as your answer’s options , which is never said so in the question.

]]>It’s the same as: “This statement is false”. Is the statement True or False?

The statement is true, the answer of the statement is false, therefore the statement is true and false or neither true nor false…

So by selecting 1, 2, 3, all or none of the answers would be correct and incorrect or neither correct nor incorrect.

]]>Nowhere does it indicate you must choose from the four choices listed below, nor are there any instructions that say you must even consider those options. It is superflous information, yet everyone assumes you MUST treat the question as such because they have been culturally trained to.

The answer to this logic question is 50%, because if you choose any answer to any question at random, you are either correct or incorrect. You might even be someone who believes that questions have no answers and that existence has no meaning (0%) OR you are a relativist, who believes questions can have more than one answer, and that there is no right or wrong, black or white, but everything is gray (100%) But even in those cases, it is human nature to think that the people who are diametrically opposed to *your* point-of-view are “wrong” and that your view is “correct” …

So, again: 50%.

]]>If I assume A or D is correct I would have 25% chance of randomly selecting B; which in turn is the probability that I selected A or D.

]]>“If you choose an answer to this question at random”

CHOSE ANY ANSWER, a, b, c or d.

and now…

“what is the chance you will be correct?”

in my mind… “well, I chose A”.

the chances of beeing correct are 50%!

You have to calculate the chances of beeing correct of a chosen answer!

B. 50%, now i`m sure 100% ðŸ™‚

So I must chose an answer to the question “what is the chance to be correct…?”

1. I want to see the chance to be correct.

1a. If I chose A, I chose D too. So the chance it`s not 25%, it`s 50%. So B. But 50%, it`s only 1/4 in my answer, so it`s not correct. = A, B, D ~ paradox, or a chance X

1b. If I chose B, it`s probably correct, no? I don`t know. So let`s say the chance it`s Y.

1c. We have X+Y chance to be correct.

2. If I want to see the chance to be incorrect.

2a. If I chose A, i chose D, so A, D = incorrect, I have 50% chance of beeing incorrect, but B is not the answer. So, again A, B, D ~ paradox, let`s say Z

2b. If I chose C, the chance is a the same number Y

BUT WAIT!

paradox X it`s the same with paradox Z!

Paradox X + number Y = Paradox Z + number Y!

We talk about chance, so it`s a proportion, and the chance of beeing correct + the chance of beeing incorrect are complementary. The chances are equal, so we have 50% chance of beeing correct and 50% chance of beeing incorrect.

So the answer is B, 50%.

(but I`s sure of that 50%. So the chances are 25% :)) ) ]]>

@longy: But there is only a 25% chance of choosing 50% at random.

]]>It’s a simple question with a simple answer that people try and complicate. ]]>