Applying this line of reasoning to the chicken and egg problem, and assuming that the chickens lay eggs in rotation, the interval between successive egg layings by any one chicken is 100/9 days. Now we have 18 chickens laying in rotation, so the interval between egg layings by *any* chicken is 100/162 days. If we start measuring as the first egg is laid, 100 eggs will have been laid at the end of 99 such intervals, or 9900/162 = 61.1111… days, or 61 days 2 hours 40 minutes.

]]>More to the question, I think Andrew touches on the real problem, but mis-states it. The author assumes the chickens are continuously laying eggs as in if a chicken can lay an egg in 10 days then in 5 days it will lay half an agg. That’s a sore, sore chicken.

]]>To Xamuel: is that a soccer ball on the cover? ugh.. Looks like one, it must be the logo of the series, I guess it is supposed to represent one of the Platonic solids.

]]>I’ve always said: no matter how many irrelevant pictures of race cars and motorcycles you stick in your math book, people are still going to assume it’s a tome of black magic. You might as well make it *look* like a tome of black magic, because at least that way it’s *cool* ðŸ™‚

Of course, this begs the question: is that a soccer ball on the cover? ugh..

]]>Actually, the biggest problem I see is that those chickens would be stew. Normal chickens lay an egg a day, or in the winter somewhat less. But one egg in 10 days? She’s not doing her share…

]]>I solved it by thinking…

(a) a chicken can lay an egg in 10 days.

(b) therefore, in 50 days, 18 chickens can lay 90 eggs.

(c) the last 10 will take another 10 days regardless – i.e. 60 days all up.

The 18 chickens can’t suddenly “rush out” the last 10 eggs in 5.5 days!

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