It could be, but only if you’re not using a base-10 counting system. Since your number is 12 digits long, it must allow for the possibility of at least 1 “10” “11” or “12” which, in standard base-10 counting, are 2 digits, not 1. for example, with a 12 digit number, you could have “11, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0” However, as you can see, for this to work, you need a 2-digit number.

If you’re using something like hexadecimal counting (where 10, 11, 12, 13, 14, and 15 are written as a single digit using letters of the alphabet A=10, B=11, ect) you could make a autobiographical number of more than 10 digits. In fact both “B000000000010000” and “9210000001000” would be valid autobiographical numbers for a base-16 (hexidecimal) or base-12 counting system, respectively.

Does that make sense? I’m not sure if I explained that well.

]]>For finding ‘n’ digit number

((n-4)*(10^(n-1)))+(2*(10^(n-2)))+(10^(n-3))+(10^3)

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